7-(1/2c)=1/4c-7

Solution for 7-(1/2c)=1/4c-7 equation:

7-(1/2c)=1/4c-7

We move all terms to the left:

7-(1/2c)-(1/4c-7)=0


Domain of the equation: 2c)!=0

c!=0/1

c!=0

c∈R



Domain of the equation: 4c-7)!=0

c∈R


We add all the numbers together, and all the variables

-(+1/2c)-(1/4c-7)+7=0

We get rid of parentheses

-1/2c-1/4c+7+7=0

We calculate fractions


(-4c)/8c^2+(-2c)/8c^2+7+7=0

We add all the numbers together, and all the variables

(-4c)/8c^2+(-2c)/8c^2+14=0

We multiply all the terms by the denominator


(-4c)+(-2c)+14*8c^2=0

Wy multiply elements

112c^2+(-4c)+(-2c)=0

We get rid of parentheses

112c^2-4c-2c=0

We add all the numbers together, and all the variables

112c^2-6c=0

a = 112; b = -6; c = 0;
Δ = b2-4ac
Δ = -62-4·112·0
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{36}=6$
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-6}{2*112}=\frac{0}{224}
=0
$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+6}{2*112}=\frac{12}{224}
=3/56
$