4x-2(1-x)=(3x-2)

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Solution for 4x-2(1-x)=(3x-2) equation: 



4x-2(1-x)=(3x-2)

We move all terms to the left:

4x-2(1-x)-((3x-2))=0

We add all the numbers together, and all the variables

4x-2(-1x+1)-((3x-2))=0

We multiply parentheses

4x+2x-((3x-2))-2=0



We calculate terms in parentheses: -((3x-2)), so:

(3x-2)

We get rid of parentheses

3x-2

Back to the equation:

-(3x-2)



We add all the numbers together, and all the variables

6x-(3x-2)-2=0

We get rid of parentheses

6x-3x+2-2=0

We add all the numbers together, and all the variables

3x=0

x=0/3

x=0

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