1/3y+10=12

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Solution for 1/3y+10=12 equation: 



1/3y+10=12

We move all terms to the left:

1/3y+10-(12)=0



Domain of the equation: 3y!=0

y!=0/3

y!=0

y∈R



We add all the numbers together, and all the variables

1/3y-2=0

We multiply all the terms by the denominator


-2*3y+1=0

Wy multiply elements

-6y+1=0

We move all terms containing y to the left, all other terms to the right

-6y=-1

y=-1/-6

y=1/6

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