4x-(3(x=12)+1)=10

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Solution for 4x-(3(x=12)+1)=10 equation: 



4x-(3(x=12)+1)=10

We move all terms to the left:

4x-(3(x-(12)+1))=0

We add all the numbers together, and all the variables

4x-(3(x-11))=0



We calculate terms in parentheses: -(3(x-11)), so:

3(x-11)

We multiply parentheses

3x-33

Back to the equation:

-(3x-33)



We get rid of parentheses

4x-3x+33=0

We add all the numbers together, and all the variables

x+33=0

We move all terms containing x to the left, all other terms to the right

x=-33

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