(7x-20)+(160-3x)=180

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Solution for (7x-20)+(160-3x)=180 equation: 



(7x-20)+(160-3x)=180

We move all terms to the left:

(7x-20)+(160-3x)-(180)=0

We add all the numbers together, and all the variables

(7x-20)+(-3x+160)-180=0

We get rid of parentheses

7x-3x-20+160-180=0

We add all the numbers together, and all the variables

4x-40=0

We move all terms containing x to the left, all other terms to the right

4x=40

x=40/4

x=10

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