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4x+3(x-4)-1(x+2)=6
We move all terms to the left:
4x+3(x-4)-1(x+2)-(6)=0
We multiply parentheses
4x+3x-1(x+2)-12-6=0
We add all the numbers together, and all the variables
7x-1(x+2)-18=0
We move all terms containing x to the left, all other terms to the right
7x-1(x+2)=18
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