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6(b-4)=2(3b-5)
We move all terms to the left:
6(b-4)-(2(3b-5))=0
We multiply parentheses
6b-(2(3b-5))-24=0
We calculate terms in parentheses: -(2(3b-5)), so:We get rid of parentheses
2(3b-5)
We multiply parentheses
6b-10
Back to the equation:
-(6b-10)
6b-6b+10-24=0
We add all the numbers together, and all the variables
-14!=0
There is no solution for this equation
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