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4x+3(2x-4)=9(x+2)
We move all terms to the left:
4x+3(2x-4)-(9(x+2))=0
We multiply parentheses
4x+6x-(9(x+2))-12=0
We calculate terms in parentheses: -(9(x+2)), so:We add all the numbers together, and all the variables
9(x+2)
We multiply parentheses
9x+18
Back to the equation:
-(9x+18)
10x-(9x+18)-12=0
We get rid of parentheses
10x-9x-18-12=0
We add all the numbers together, and all the variables
x-30=0
We move all terms containing x to the left, all other terms to the right
x=30
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