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8(x+1)-9=6x+2(2+x)
We move all terms to the left:
8(x+1)-9-(6x+2(2+x))=0
We add all the numbers together, and all the variables
8(x+1)-(6x+2(x+2))-9=0
We multiply parentheses
8x-(6x+2(x+2))+8-9=0
We calculate terms in parentheses: -(6x+2(x+2)), so:We add all the numbers together, and all the variables
6x+2(x+2)
We multiply parentheses
6x+2x+4
We add all the numbers together, and all the variables
8x+4
Back to the equation:
-(8x+4)
8x-(8x+4)-1=0
We get rid of parentheses
8x-8x-4-1=0
We add all the numbers together, and all the variables
-5!=0
There is no solution for this equation
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