4x+2(2x-3)=4(x-2)

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Solution for 4x+2(2x-3)=4(x-2) equation: 



4x+2(2x-3)=4(x-2)

We move all terms to the left:

4x+2(2x-3)-(4(x-2))=0

We multiply parentheses

4x+4x-(4(x-2))-6=0



We calculate terms in parentheses: -(4(x-2)), so:

4(x-2)

We multiply parentheses

4x-8

Back to the equation:

-(4x-8)



We add all the numbers together, and all the variables

8x-(4x-8)-6=0

We get rid of parentheses

8x-4x+8-6=0

We add all the numbers together, and all the variables

4x+2=0

We move all terms containing x to the left, all other terms to the right

4x=-2

x=-2/4

x=-1/2

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