(3y-2)=(y+10)

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Solution for (3y-2)=(y+10) equation: 



(3y-2)=(y+10)

We move all terms to the left:

(3y-2)-((y+10))=0

We get rid of parentheses

3y-((y+10))-2=0



We calculate terms in parentheses: -((y+10)), so:

(y+10)

We get rid of parentheses

y+10

Back to the equation:

-(y+10)



We get rid of parentheses

3y-y-10-2=0

We add all the numbers together, and all the variables

2y-12=0

We move all terms containing y to the left, all other terms to the right

2y=12

y=12/2

y=6

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