4x+2(20-x)=56

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Solution for 4x+2(20-x)=56 equation: 



4x+2(20-x)=56

We move all terms to the left:

4x+2(20-x)-(56)=0

We add all the numbers together, and all the variables

4x+2(-1x+20)-56=0

We multiply parentheses

4x-2x+40-56=0

We add all the numbers together, and all the variables

2x-16=0

We move all terms containing x to the left, all other terms to the right

2x=16

x=16/2

x=8

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