4x+19=3(2x-2)+5

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Solution for 4x+19=3(2x-2)+5 equation: 



4x+19=3(2x-2)+5

We move all terms to the left:

4x+19-(3(2x-2)+5)=0



We calculate terms in parentheses: -(3(2x-2)+5), so:

3(2x-2)+5

We multiply parentheses

6x-6+5

We add all the numbers together, and all the variables

6x-1

Back to the equation:

-(6x-1)



We get rid of parentheses

4x-6x+1+19=0

We add all the numbers together, and all the variables

-2x+20=0

We move all terms containing x to the left, all other terms to the right

-2x=-20

x=-20/-2

x=+10

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