11(2x-1)=8(2x+1)+41

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Solution for 11(2x-1)=8(2x+1)+41 equation: 



11(2x-1)=8(2x+1)+41

We move all terms to the left:

11(2x-1)-(8(2x+1)+41)=0

We multiply parentheses

22x-(8(2x+1)+41)-11=0



We calculate terms in parentheses: -(8(2x+1)+41), so:

8(2x+1)+41

We multiply parentheses

16x+8+41

We add all the numbers together, and all the variables

16x+49

Back to the equation:

-(16x+49)



We get rid of parentheses

22x-16x-49-11=0

We add all the numbers together, and all the variables

6x-60=0

We move all terms containing x to the left, all other terms to the right

6x=60

x=60/6

x=10

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