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4x*12x=120
We move all terms to the left:
4x*12x-(120)=0
Wy multiply elements
48x^2-120=0
a = 48; b = 0; c = -120;
Δ = b2-4ac
Δ = 02-4·48·(-120)
Δ = 23040
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{23040}=\sqrt{2304*10}=\sqrt{2304}*\sqrt{10}=48\sqrt{10}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-48\sqrt{10}}{2*48}=\frac{0-48\sqrt{10}}{96} =-\frac{48\sqrt{10}}{96} =-\frac{\sqrt{10}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+48\sqrt{10}}{2*48}=\frac{0+48\sqrt{10}}{96} =\frac{48\sqrt{10}}{96} =\frac{\sqrt{10}}{2} $
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