4x(x-4)+5(8-x)=7x-(6+2x)

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Solution for 4x(x-4)+5(8-x)=7x-(6+2x) equation: 



4x(x-4)+5(8-x)=7x-(6+2x)

We move all terms to the left:

4x(x-4)+5(8-x)-(7x-(6+2x))=0

We add all the numbers together, and all the variables

4x(x-4)+5(-1x+8)-(7x-(2x+6))=0

We multiply parentheses

4x^2-16x-5x-(7x-(2x+6))+40=0



We calculate terms in parentheses: -(7x-(2x+6)), so:

7x-(2x+6)

We get rid of parentheses

7x-2x-6

We add all the numbers together, and all the variables

5x-6

Back to the equation:

-(5x-6)



We add all the numbers together, and all the variables

4x^2-21x-(5x-6)+40=0

We get rid of parentheses

4x^2-21x-5x+6+40=0

We add all the numbers together, and all the variables

4x^2-26x+46=0

a = 4; b = -26; c = +46;
Δ = b2-4ac
Δ = -262-4·4·46
Δ = -60
Delta is less than zero, so there is no solution for the equation

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