750+20(n-5)=650+30(n-10)

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Solution for 750+20(n-5)=650+30(n-10) equation: 



750+20(n-5)=650+30(n-10)

We move all terms to the left:

750+20(n-5)-(650+30(n-10))=0

We multiply parentheses

20n-(650+30(n-10))-100+750=0



We calculate terms in parentheses: -(650+30(n-10)), so:

650+30(n-10)

determiningTheFunctionDomain
30(n-10)+650

We multiply parentheses

30n-300+650

We add all the numbers together, and all the variables

30n+350

Back to the equation:

-(30n+350)



We add all the numbers together, and all the variables

20n-(30n+350)+650=0

We get rid of parentheses

20n-30n-350+650=0

We add all the numbers together, and all the variables

-10n+300=0

We move all terms containing n to the left, all other terms to the right

-10n=-300

n=-300/-10

n=+30

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