4x(x-3)=x(4x-5)+2

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Solution for 4x(x-3)=x(4x-5)+2 equation: 



4x(x-3)=x(4x-5)+2

We move all terms to the left:

4x(x-3)-(x(4x-5)+2)=0

We multiply parentheses

4x^2-12x-(x(4x-5)+2)=0



We calculate terms in parentheses: -(x(4x-5)+2), so:

x(4x-5)+2

We multiply parentheses

4x^2-5x+2

Back to the equation:

-(4x^2-5x+2)



We get rid of parentheses

4x^2-4x^2-12x+5x-2=0

We add all the numbers together, and all the variables

-7x-2=0

We move all terms containing x to the left, all other terms to the right

-7x=2

x=2/-7

x=-2/7

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