2x+1/2+3x+4/3+x+5/6=2

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Solution for 2x+1/2+3x+4/3+x+5/6=2 equation: 



2x+1/2+3x+4/3+x+5/6=2

We move all terms to the left:

2x+1/2+3x+4/3+x+5/6-(2)=0

determiningTheFunctionDomain
2x+3x+x-2+1/2+4/3+5/6=0

We add all the numbers together, and all the variables

6x-2+1/2+4/3+5/6=0

We calculate fractions

There is no solution for this equation

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