2(3y-2)-4(2y-5)=8

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Solution for 2(3y-2)-4(2y-5)=8 equation: 



2(3y-2)-4(2y-5)=8

We move all terms to the left:

2(3y-2)-4(2y-5)-(8)=0

We multiply parentheses

6y-8y-4+20-8=0

We add all the numbers together, and all the variables

-2y+8=0

We move all terms containing y to the left, all other terms to the right

-2y=-8

y=-8/-2

y=+4

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