4x(x-2)=4(x2-3)-4

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Solution for 4x(x-2)=4(x2-3)-4 equation: 



4x(x-2)=4(x2-3)-4

We move all terms to the left:

4x(x-2)-(4(x2-3)-4)=0

We add all the numbers together, and all the variables

-(4(+x^2-3)-4)+4x(x-2)=0

We multiply parentheses

-(4(+x^2-3)-4)+4x^2-8x=0



We calculate terms in parentheses: -(4(+x^2-3)-4), so:

4(+x^2-3)-4

We multiply parentheses

4x^2-12-4

We add all the numbers together, and all the variables

4x^2-16

Back to the equation:

-(4x^2-16)



We add all the numbers together, and all the variables

4x^2-8x-(4x^2-16)=0

We get rid of parentheses

4x^2-4x^2-8x+16=0

We add all the numbers together, and all the variables

-8x+16=0

We move all terms containing x to the left, all other terms to the right

-8x=-16

x=-16/-8

x=+2

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