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(1/3)(4x+5)=8x
We move all terms to the left:
(1/3)(4x+5)-(8x)=0
Domain of the equation: 3)(4x+5)!=0We add all the numbers together, and all the variables
x∈R
(+1/3)(4x+5)-8x=0
We add all the numbers together, and all the variables
-8x+(+1/3)(4x+5)=0
We multiply parentheses ..
(+4x^2+1/3*5)-8x=0
We multiply all the terms by the denominator
(+4x^2+1-8x*3*5)=0
We get rid of parentheses
4x^2-8x*3*5+1=0
Wy multiply elements
4x^2-120x*5+1=0
Wy multiply elements
4x^2-600x+1=0
a = 4; b = -600; c = +1;
Δ = b2-4ac
Δ = -6002-4·4·1
Δ = 359984
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{359984}=\sqrt{16*22499}=\sqrt{16}*\sqrt{22499}=4\sqrt{22499}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-600)-4\sqrt{22499}}{2*4}=\frac{600-4\sqrt{22499}}{8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-600)+4\sqrt{22499}}{2*4}=\frac{600+4\sqrt{22499}}{8} $
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