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4x(x-1)=2(x*x+27)
We move all terms to the left:
4x(x-1)-(2(x*x+27))=0
We multiply parentheses
4x^2-4x-(2(x*x+27))=0
We calculate terms in parentheses: -(2(x*x+27)), so:We get rid of parentheses
2(x*x+27)
We multiply parentheses
2x^2+54
Back to the equation:
-(2x^2+54)
4x^2-2x^2-4x-54=0
We add all the numbers together, and all the variables
2x^2-4x-54=0
a = 2; b = -4; c = -54;
Δ = b2-4ac
Δ = -42-4·2·(-54)
Δ = 448
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{448}=\sqrt{64*7}=\sqrt{64}*\sqrt{7}=8\sqrt{7}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4)-8\sqrt{7}}{2*2}=\frac{4-8\sqrt{7}}{4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4)+8\sqrt{7}}{2*2}=\frac{4+8\sqrt{7}}{4} $
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