8(x-1)=2(3x-1)+(1-2x)

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Solution for 8(x-1)=2(3x-1)+(1-2x) equation: 



8(x-1)=2(3x-1)+(1-2x)

We move all terms to the left:

8(x-1)-(2(3x-1)+(1-2x))=0

We add all the numbers together, and all the variables

8(x-1)-(2(3x-1)+(-2x+1))=0

We multiply parentheses

8x-(2(3x-1)+(-2x+1))-8=0



We calculate terms in parentheses: -(2(3x-1)+(-2x+1)), so:

2(3x-1)+(-2x+1)

We multiply parentheses

6x+(-2x+1)-2

We get rid of parentheses

6x-2x+1-2

We add all the numbers together, and all the variables

4x-1

Back to the equation:

-(4x-1)



We get rid of parentheses

8x-4x+1-8=0

We add all the numbers together, and all the variables

4x-7=0

We move all terms containing x to the left, all other terms to the right

4x=7

x=7/4

x=1+3/4

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