4x(6x-10)=0

Solution for 4x(6x-10)=0 equation:

4x(6x-10)=0

We multiply parentheses

24x^2-40x=0

a = 24; b = -40; c = 0;
Δ = b2-4ac
Δ = -402-4·24·0
Δ = 1600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1600}=40$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-40)-40}{2*24}=\frac{0}{48}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-40)+40}{2*24}=\frac{80}{48}
=1+2/3
$