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12x=9x^2+4
We move all terms to the left:
12x-(9x^2+4)=0
We get rid of parentheses
-9x^2+12x-4=0
a = -9; b = 12; c = -4;
Δ = b2-4ac
Δ = 122-4·(-9)·(-4)
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$x=\frac{-b}{2a}=\frac{-12}{-18}=2/3$
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