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4x(3x+3)-2(3x-5)=5
We move all terms to the left:
4x(3x+3)-2(3x-5)-(5)=0
We multiply parentheses
12x^2+12x-6x+10-5=0
We add all the numbers together, and all the variables
12x^2+6x+5=0
a = 12; b = 6; c = +5;
Δ = b2-4ac
Δ = 62-4·12·5
Δ = -204
Delta is less than zero, so there is no solution for the equation
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