If it's not what You are looking for type in the equation solver your own equation and let us solve it.
4x^2-7x+2=0
a = 4; b = -7; c = +2;
Δ = b2-4ac
Δ = -72-4·4·2
Δ = 17
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7)-\sqrt{17}}{2*4}=\frac{7-\sqrt{17}}{8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7)+\sqrt{17}}{2*4}=\frac{7+\sqrt{17}}{8} $
| X^2+36/x^2=13 | | 9x-16=4x+5 | | 22=12/x | | 0.50x+3=x | | -3x^2-30x+8=0 | | 3x^2-30x+8=0 | | 4(x-1)-(x-8)=0 | | 6a-2=5a+2 | | 6y-y2=8 | | x17=1/2(156x-17) | | Q/2=28,q=14 | | 3(3y-6)=8 | | 5(2y+)=20 | | x^2+2x-5=22 | | z/9+9=-2 | | X+0,04x+250=22714 | | 2X2-x=6 | | 2p+1=175 | | 2t+2=3t | | 3=-2r+23 | | 2x÷5-8=3÷5x | | 4(3x-1)=2(5x+4) | | 10t+4=4t+10 | | ((5x-7)/2)-3x+14=(2x-7)/3 | | (2x+16)=(x+12) | | X+1/3-5x-12/9=1 | | -9c-1=-1 | | 57=4y+13 | | 2*(u-1)=3*(u-1) | | 2*(y-5)=y+10 | | 5*(3-y)-12,5=0 | | 14t-7=4t-2 |