4x(12x+4)=15+2

Solution for 4x(12x+4)=15+2 equation:

4x(12x+4)=15+2

We move all terms to the left:

4x(12x+4)-(15+2)=0

We add all the numbers together, and all the variables

4x(12x+4)-17=0

We multiply parentheses

48x^2+16x-17=0

a = 48; b = 16; c = -17;
Δ = b2-4ac
Δ = 162-4·48·(-17)
Δ = 3520
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{3520}=\sqrt{64*55}=\sqrt{64}*\sqrt{55}=8\sqrt{55}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(16)-8\sqrt{55}}{2*48}=\frac{-16-8\sqrt{55}}{96}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(16)+8\sqrt{55}}{2*48}=\frac{-16+8\sqrt{55}}{96}
$