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4(2x-1)+2(x-5)=5(x+1)+3
We move all terms to the left:
4(2x-1)+2(x-5)-(5(x+1)+3)=0
We multiply parentheses
8x+2x-(5(x+1)+3)-4-10=0
We calculate terms in parentheses: -(5(x+1)+3), so:We add all the numbers together, and all the variables
5(x+1)+3
We multiply parentheses
5x+5+3
We add all the numbers together, and all the variables
5x+8
Back to the equation:
-(5x+8)
10x-(5x+8)-14=0
We get rid of parentheses
10x-5x-8-14=0
We add all the numbers together, and all the variables
5x-22=0
We move all terms containing x to the left, all other terms to the right
5x=22
x=22/5
x=4+2/5
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