4w2+24w=0

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Solution for 4w2+24w=0 equation: 



4w^2+24w=0

a = 4; b = 24; c = 0;
Δ = b2-4ac
Δ = 242-4·4·0
Δ = 576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{576}=24$


$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(24)-24}{2*4}=\frac{-48}{8}
=-6
$


$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(24)+24}{2*4}=\frac{0}{8}
=0
$

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