4v-9+3(2v+5)=-2(v+2)

Solution for 4v-9+3(2v+5)=-2(v+2) equation:

4v-9+3(2v+5)=-2(v+2)

We move all terms to the left:

4v-9+3(2v+5)-(-2(v+2))=0

We multiply parentheses

4v+6v-(-2(v+2))+15-9=0


We calculate terms in parentheses: -(-2(v+2)), so:

-2(v+2)

We multiply parentheses

-2v-4

Back to the equation:

-(-2v-4)


We add all the numbers together, and all the variables

10v-(-2v-4)+6=0

We get rid of parentheses

10v+2v+4+6=0

We add all the numbers together, and all the variables

12v+10=0

We move all terms containing v to the left, all other terms to the right

12v=-10

v=-10/12

v=-5/6