2(3m+2)=7(1+m)-2m

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Solution for 2(3m+2)=7(1+m)-2m equation: 



2(3m+2)=7(1+m)-2m

We move all terms to the left:

2(3m+2)-(7(1+m)-2m)=0

We add all the numbers together, and all the variables

2(3m+2)-(7(m+1)-2m)=0

We multiply parentheses

6m-(7(m+1)-2m)+4=0



We calculate terms in parentheses: -(7(m+1)-2m), so:

7(m+1)-2m

We add all the numbers together, and all the variables

-2m+7(m+1)

We multiply parentheses

-2m+7m+7

We add all the numbers together, and all the variables

5m+7

Back to the equation:

-(5m+7)



We get rid of parentheses

6m-5m-7+4=0

We add all the numbers together, and all the variables

m-3=0

We move all terms containing m to the left, all other terms to the right

m=3

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