4v+2=2(v-2)

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Solution for 4v+2=2(v-2) equation: 



4v+2=2(v-2)

We move all terms to the left:

4v+2-(2(v-2))=0



We calculate terms in parentheses: -(2(v-2)), so:

2(v-2)

We multiply parentheses

2v-4

Back to the equation:

-(2v-4)



We get rid of parentheses

4v-2v+4+2=0

We add all the numbers together, and all the variables

2v+6=0

We move all terms containing v to the left, all other terms to the right

2v=-6

v=-6/2

v=-3

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