14-3(5t-12)=1-(20t+1)14

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Solution for 14-3(5t-12)=1-(20t+1)14 equation: 



14-3(5t-12)=1-(20t+1)14

We move all terms to the left:

14-3(5t-12)-(1-(20t+1)14)=0

We multiply parentheses

-15t-(1-(20t+1)14)+36+14=0



We calculate terms in parentheses: -(1-(20t+1)14), so:

1-(20t+1)14

determiningTheFunctionDomain
-(20t+1)14+1

We multiply parentheses

-280t-14+1

We add all the numbers together, and all the variables

-280t-13

Back to the equation:

-(-280t-13)



We add all the numbers together, and all the variables

-15t-(-280t-13)+50=0

We get rid of parentheses

-15t+280t+13+50=0

We add all the numbers together, and all the variables

265t+63=0

We move all terms containing t to the left, all other terms to the right

265t=-63

t=-63/265

t=-63/265

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