4u-8+2(2u+4)=-6(u+3)

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Solution for 4u-8+2(2u+4)=-6(u+3) equation: 



4u-8+2(2u+4)=-6(u+3)

We move all terms to the left:

4u-8+2(2u+4)-(-6(u+3))=0

We multiply parentheses

4u+4u-(-6(u+3))+8-8=0



We calculate terms in parentheses: -(-6(u+3)), so:

-6(u+3)

We multiply parentheses

-6u-18

Back to the equation:

-(-6u-18)



We add all the numbers together, and all the variables

8u-(-6u-18)=0

We get rid of parentheses

8u+6u+18=0

We add all the numbers together, and all the variables

14u+18=0

We move all terms containing u to the left, all other terms to the right

14u=-18

u=-18/14

u=-1+2/7

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