4u-3=4(2-u)-3

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Solution for 4u-3=4(2-u)-3 equation: 



4u-3=4(2-u)-3

We move all terms to the left:

4u-3-(4(2-u)-3)=0

We add all the numbers together, and all the variables

4u-(4(-1u+2)-3)-3=0



We calculate terms in parentheses: -(4(-1u+2)-3), so:

4(-1u+2)-3

We multiply parentheses

-4u+8-3

We add all the numbers together, and all the variables

-4u+5

Back to the equation:

-(-4u+5)



We get rid of parentheses

4u+4u-5-3=0

We add all the numbers together, and all the variables

8u-8=0

We move all terms containing u to the left, all other terms to the right

8u=8

u=8/8

u=1

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