4t*4t=16t

Solution for 4t*4t=16t equation:

4t*4t=16t

We move all terms to the left:

4t*4t-(16t)=0

We add all the numbers together, and all the variables

-16t+4t*4t=0

Wy multiply elements

16t^2-16t=0

a = 16; b = -16; c = 0;
Δ = b2-4ac
Δ = -162-4·16·0
Δ = 256
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{256}=16$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-16)-16}{2*16}=\frac{0}{32}
=0
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-16)+16}{2*16}=\frac{32}{32}
=1
$