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1/3x-24=x-8
We move all terms to the left:
1/3x-24-(x-8)=0
Domain of the equation: 3x!=0We get rid of parentheses
x!=0/3
x!=0
x∈R
1/3x-x+8-24=0
We multiply all the terms by the denominator
-x*3x+8*3x-24*3x+1=0
Wy multiply elements
-3x^2+24x-72x+1=0
We add all the numbers together, and all the variables
-3x^2-48x+1=0
a = -3; b = -48; c = +1;
Δ = b2-4ac
Δ = -482-4·(-3)·1
Δ = 2316
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{2316}=\sqrt{4*579}=\sqrt{4}*\sqrt{579}=2\sqrt{579}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-48)-2\sqrt{579}}{2*-3}=\frac{48-2\sqrt{579}}{-6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-48)+2\sqrt{579}}{2*-3}=\frac{48+2\sqrt{579}}{-6} $
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