4s+2=3(2s-1)+21

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Solution for 4s+2=3(2s-1)+21 equation: 



4s+2=3(2s-1)+21

We move all terms to the left:

4s+2-(3(2s-1)+21)=0



We calculate terms in parentheses: -(3(2s-1)+21), so:

3(2s-1)+21

We multiply parentheses

6s-3+21

We add all the numbers together, and all the variables

6s+18

Back to the equation:

-(6s+18)



We get rid of parentheses

4s-6s-18+2=0

We add all the numbers together, and all the variables

-2s-16=0

We move all terms containing s to the left, all other terms to the right

-2s=16

s=16/-2

s=-8

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