(2x+30)+(3x-10)+(7x-32)=180

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Solution for (2x+30)+(3x-10)+(7x-32)=180 equation: 



(2x+30)+(3x-10)+(7x-32)=180

We move all terms to the left:

(2x+30)+(3x-10)+(7x-32)-(180)=0

We get rid of parentheses

2x+3x+7x+30-10-32-180=0

We add all the numbers together, and all the variables

12x-192=0

We move all terms containing x to the left, all other terms to the right

12x=192

x=192/12

x=16

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