4r+1=2(2r+3)

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Solution for 4r+1=2(2r+3) equation: 



4r+1=2(2r+3)

We move all terms to the left:

4r+1-(2(2r+3))=0



We calculate terms in parentheses: -(2(2r+3)), so:

2(2r+3)

We multiply parentheses

4r+6

Back to the equation:

-(4r+6)



We get rid of parentheses

4r-4r-6+1=0

We add all the numbers together, and all the variables

-5!=0

There is no solution for this equation

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