6u-4+2(3u+9)=-2(u+1)

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Solution for 6u-4+2(3u+9)=-2(u+1) equation:



6u-4+2(3u+9)=-2(u+1)
We move all terms to the left:
6u-4+2(3u+9)-(-2(u+1))=0
We multiply parentheses
6u+6u-(-2(u+1))+18-4=0
We calculate terms in parentheses: -(-2(u+1)), so:
-2(u+1)
We multiply parentheses
-2u-2
Back to the equation:
-(-2u-2)
We add all the numbers together, and all the variables
12u-(-2u-2)+14=0
We get rid of parentheses
12u+2u+2+14=0
We add all the numbers together, and all the variables
14u+16=0
We move all terms containing u to the left, all other terms to the right
14u=-16
u=-16/14
u=-1+1/7

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