4q=1.65+(9q/15)

Solution for 4q=1.65+(9q/15) equation:

4q=1.65+(9q/15)

We move all terms to the left:

4q-(1.65+(9q/15))=0

We add all the numbers together, and all the variables

4q-(1.65+(+9q/15))=0

We multiply all the terms by the denominator


4q*15))-(1.65+(+9q=0

We add all the numbers together, and all the variables

9q+4q*15))-(1.65+(=0

Wy multiply elements

60q^2+9q=0

a = 60; b = 9; c = 0;
Δ = b2-4ac
Δ = 92-4·60·0
Δ = 81
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$q_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$q_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{81}=9$
$q_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-9}{2*60}=\frac{-18}{120}
=-3/20
$
$q_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+9}{2*60}=\frac{0}{120}
=0
$