4q=3(0.55+(3q/5))

Solution for 4q=3(0.55+(3q/5)) equation:

4q=3(0.55+(3q/5))

We move all terms to the left:

4q-(3(0.55+(3q/5)))=0

We add all the numbers together, and all the variables

4q-(3(0.55+(+3q/5)))=0

We multiply all the terms by the denominator


4q*5)))-(3(0.55+(+3q=0

We add all the numbers together, and all the variables

3q+4q*5)))-(3(0.55+(=0

Wy multiply elements

20q^2+3q=0

a = 20; b = 3; c = 0;
Δ = b2-4ac
Δ = 32-4·20·0
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$q_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$q_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{9}=3$
$q_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-3}{2*20}=\frac{-6}{40}
=-3/20
$
$q_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+3}{2*20}=\frac{0}{40}
=0
$