4n2+4n-366=0

Solution for 4n2+4n-366=0 equation:

4n^2+4n-366=0

a = 4; b = 4; c = -366;
Δ = b2-4ac
Δ = 42-4·4·(-366)
Δ = 5872
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{5872}=\sqrt{16*367}=\sqrt{16}*\sqrt{367}=4\sqrt{367}$
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-4\sqrt{367}}{2*4}=\frac{-4-4\sqrt{367}}{8}
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+4\sqrt{367}}{2*4}=\frac{-4+4\sqrt{367}}{8}
$