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1/2x+2-3/2x=21-2+x
We move all terms to the left:
1/2x+2-3/2x-(21-2+x)=0
Domain of the equation: 2x!=0We add all the numbers together, and all the variables
x!=0/2
x!=0
x∈R
1/2x-3/2x-(x+19)+2=0
We get rid of parentheses
1/2x-3/2x-x-19+2=0
We multiply all the terms by the denominator
-x*2x-19*2x+2*2x+1-3=0
We add all the numbers together, and all the variables
-x*2x-19*2x+2*2x-2=0
Wy multiply elements
-2x^2-38x+4x-2=0
We add all the numbers together, and all the variables
-2x^2-34x-2=0
a = -2; b = -34; c = -2;
Δ = b2-4ac
Δ = -342-4·(-2)·(-2)
Δ = 1140
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1140}=\sqrt{4*285}=\sqrt{4}*\sqrt{285}=2\sqrt{285}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-34)-2\sqrt{285}}{2*-2}=\frac{34-2\sqrt{285}}{-4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-34)+2\sqrt{285}}{2*-2}=\frac{34+2\sqrt{285}}{-4} $
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