4n-2(3-n)=-12

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Solution for 4n-2(3-n)=-12 equation: 



4n-2(3-n)=-12

We move all terms to the left:

4n-2(3-n)-(-12)=0

We add all the numbers together, and all the variables

4n-2(-1n+3)-(-12)=0

We add all the numbers together, and all the variables

4n-2(-1n+3)+12=0

We multiply parentheses

4n+2n-6+12=0

We add all the numbers together, and all the variables

6n+6=0

We move all terms containing n to the left, all other terms to the right

6n=-6

n=-6/6

n=-1

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