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(3x-6)=(x+11)
We move all terms to the left:
(3x-6)-((x+11))=0
We get rid of parentheses
3x-((x+11))-6=0
We calculate terms in parentheses: -((x+11)), so:We get rid of parentheses
(x+11)
We get rid of parentheses
x+11
Back to the equation:
-(x+11)
3x-x-11-6=0
We add all the numbers together, and all the variables
2x-17=0
We move all terms containing x to the left, all other terms to the right
2x=17
x=17/2
x=8+1/2
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