4n+6-2n=3(n+3-11)

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Solution for 4n+6-2n=3(n+3-11) equation: 



4n+6-2n=3(n+3-11)

We move all terms to the left:

4n+6-2n-(3(n+3-11))=0

We add all the numbers together, and all the variables

4n-2n-(3(n-8))+6=0

We add all the numbers together, and all the variables

2n-(3(n-8))+6=0



We calculate terms in parentheses: -(3(n-8)), so:

3(n-8)

We multiply parentheses

3n-24

Back to the equation:

-(3n-24)



We get rid of parentheses

2n-3n+24+6=0

We add all the numbers together, and all the variables

-1n+30=0

We move all terms containing n to the left, all other terms to the right

-n=-30

n=-30/-1

n=+30

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